EXPLAIN HOW TO SHOW THAT SAME ANGLE OF TRIANGLE IS EQUAL TO ONE HUNDRED EIGHTY DEGREE

Look at the picture....

EXPLAIN HOW TO PROVE THAT THE SQUARE ROOT OF TWO IS IRRATIONAL NUMBER

We know that definition of rational number is number which a number can wrote in shape x over y, which x and y is integer number not equal zero. So, square root of two is irrational number, because wrote in shape x over y.

EXPLAIN HOW TO GET PHI

Make some circle with different diameters. Then search circumference the circle using rope. And now we have circumference and diameters of each circle. Then, to each circle, put the circumference and diameters to formula circumference equal to multiplied phi with diameters. And for each circle, search value from phi. And we know we get same value of phi that is three point fourteen.

EXPLAIN HOW TO FIND OUT THE AREA OF REGION BOUNDERED BY THE GRAPH OF Y EQUAL X SQUARE AND Y EQUAL X PLUS TWO

First, equal two graph equation. And we got x square minus x minus two equal zero. And the root is minus one and two. Then put number between the roots. We put zero. Enter zero to each graph equation. And we know value of x plus two more than x square. So the graph x plus two there is upper. And then we can integrate the equation. So, integrate of minus x square plus x plus two toward x with limit from x equal minus one to x equal two. And we can get the area is twenty seven over six

EXPLAIN HOW TO DETERMINED THE E INTERSEPTION POINT BETWEEN THE CIRCLE X SQUARE PLUS Y SQUARE EQUAL TWENTY AND Y EQUAL X PLUS ONE

First, substituted y equal x plus one to x square plus y square equal twenty and we get new equation that is two x square plus two x minus nineteen equal zero. Then to know how many possible roots we can search determinant. Where, determinant equal b square minus four ac. So that, the equation have two root because the value of determinant more than zero. And know search the root. And the root is x. Then substitute x to the equation and we get y. x point y is interceptions point of two circle.

MAXIMUM AND MINIMUM VALUE (EXTREME VALUE)

Value of f(a) call maximum value at interval I, If f(a) more than f(x) to every x component of I. while Value of f(a) call minimum value at interval I, If f(a) less than f(x) to every x component of I.

The rule to determined maximum an minimum value:

· Definite first and second decrease, f’(x) and f’’(x)

· Definite stationary point from first decrease, f’(x) = 0, so that x = a

· Value f(a) as maximum value if f’’(a)<0, while value f(a) as minimum value if f’’(a)>0

Example:

Distance a motorcycle from a place calculate every at t with formula f(t) equal one to three over three minus seven square over two plus ten x. Determine maximum and minimum distance from a motorcycle.

Answer:

First, determine first and second decrease. We get of first decrease is x square minus seven x plus ten. And second decrease is two times x minus seven.

Then, determine stationer point with equally first decrease with zero. And we get two stationer points that is five and two. Then, substitute two stationer points to second decrease equation. And we get minus three for t equal two and three for t equal five. And from this situation we know that f (t) maximum on t equal two and minimum on t equal five. And substitute the stationer point to f (t) and we get maximum and minimum distance.

FIBONACCI SERIES

Unlimited Integer series, where, a number can be get from to count up two numbers before. And the formula like U0 equal U1 equal one. And U (n+1) equal U (n) plus U (n-1). And if we divide a number with number before, we can get value to approach one point six one eight. And this usually call Golden Ratio.

Sample of this series is 1, 1, 2, 3, 5, 8, 12, 13, 21, 34, 55, 89, 144........

Application of this series can be use to search how many rabbit in a room, where every a pair rabbit always produce a pair rabbit too.

PARALLEL EPIPEDUM

Parallel epipedum is prism where the base is parallelogram. So, like with ordinary prism and the different only in base.

Example we will search height of parallel epipedum with congruent parallelogram and we know area of parallel epipedum is thirty six and side of parallelogram is three. So to search the high of Parallel epipedum we must search area of each side with divide area with sum side that is thirty six with six and the result is six. And then we only searc high of side that is parallelogram with use formula base cross high. So the high of Parallel epipedum is divide six with three that is two.

Watching Video

Dead Poet’s Society

Essence of this video is to remind us to look something not only a way, but from different way. We must look something not only from side, but from other side too. Don’t look something only from bad side, but look from good side too. This video wants us to can get idea with sample object a table. How we can look the table by another side. What we can get different idea from looked the table from another side.

Believe

Essence of this video is about important of be our self. Because with be our self, we can be a good figure. To get be our selves, we must believe with our selves. Because, with believe with our selves, we can feel good. We can do anything what we want. But not enough believe with our selves. We must believe with another figure like, friend, teacher, parents, etc. because we can’t life alone, we need another figure. So we can share knowledge with another figure to supply with each other. With be our selves, we can be do anything well.

What You Know About Math?

Essence of this video is that math can study with a song, which in studied trigonometry, multiplied; exponent, etc can to pass a song. This song is ‘what you know about math? So, much option in study mathematic.

Differential and Integrate Equation

Essence of this video is how to solving differential and integrate equation. As sample, If we have dy over dx equals four times x to the power of two and get the value. We should integrate dy over dx we will get y and we will get four third times x to the power of three plus C from four times x to the power of two. This, C is constant. So the equation can search with those methods.

How to search value of variable

Some sample of problem to search variable of x.

• x minus five equals three, to search this value of variable, add five in left and right equal. So the value of variable x is eight
• seven equals four times x minus one , to search this value of variable, we can add plus one in left and right equal. So we get eight equal four times x. Then, multiply the both side with quarter. So, we can get the result is two
• Two over three times x equals eight, to search this value, we can multiply both sides with three over two, and so we can get variable of x are twelve.
• Five minus two times x equals three times x plus one, to get value, we can add plus five in both sides, so that value minus two times x equal three times x minus four. Then, add both sides with three times x, so the value is minus five times x equal minus four. Then multiply the both side with minus one over five, so we get values of variable of x is four over five
• Three minus five open brackets two times m minus five close brackets equals minus two, to get the value, we must times five with two times m minus five. So we can get three minus ten times m plus twenty five equals minus two. Then add three with minus twenty five on left sides then we get minus ten times m plus minus twenty eight equals minus two. Then add minus twenty eight in both side, so we get minus ten times m equal minus thirty. Then multiply the both side with minus one per ten. So we get value from variable m is three.
• a half times x plus a quarter equals one per three times x plus five per four. First, add the both side with minus quarter. So we get a half times x equal one over three times x plus one. Then add minus one over three times x in both sides. So we get one per six times x equal one. Then multiplied the both side with six. So we get the values is six
• Oh point thirty five times x minus oh point two equals oh point fifteen times x plus oh point one. First add minus oh point one in two sides. So we get oh point thirty five times x minus oh point three equal oh point fifteen times x. Then add minus oh point fifteen times x in both side, so we get oh point two times x minus oh point three equal zero. Then add both side with plus oh point three, and we get oh point two times x equal oh point three. Then multiplied the both side with one over oh point two. So w get value of x is three over two.

Logaritm

Essence of this video is about logarithm equation. We can proof about logarithm basic x of a equals be, so we can get the value of a. Then logarithm basic x of open bracket a to the power of B close bracket, we can change it with B times logarithm basic x of open bracket A. After we can prove that logarithm basic x of A plus logarithm basic x of B equals logarithm basic x open bracket A times B close bracket is equals. We can proof that logarithm basic x of A minus logarithm basic x of B equals logarithm basic x open bracket A over B close bracket is equals from equation.

The video can motivation us to want know deep mathematic

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