EXPLAIN HOW TO SHOW THAT SAME ANGLE OF TRIANGLE IS EQUAL TO ONE HUNDRED EIGHTY DEGREE
EXPLAIN HOW TO PROVE THAT THE SQUARE ROOT OF TWO IS IRRATIONAL NUMBER
We know that definition of rational number is number which a number can wrote in shape x over y, which x and y is integer number not equal zero. So, square root of two is irrational number, because wrote in shape x over y.
EXPLAIN HOW TO GET PHI
Make some circle with different diameters. Then search circumference the circle using rope. And now we have circumference and diameters of each circle. Then, to each circle, put the circumference and diameters to formula circumference equal to multiplied phi with diameters. And for each circle, search value from phi. And we know we get same value of phi that is three point fourteen.
EXPLAIN HOW TO FIND OUT THE AREA OF REGION BOUNDERED BY THE GRAPH OF Y EQUAL X SQUARE AND Y EQUAL X PLUS TWO
First, equal two graph equation. And we got x square minus x minus two equal zero. And the root is minus one and two. Then put number between the roots. We put zero. Enter zero to each graph equation. And we know value of x plus two more than x square. So the graph x plus two there is upper. And then we can integrate the equation. So, integrate of minus x square plus x plus two toward x with limit from x equal minus one to x equal two. And we can get the area is twenty seven over six
EXPLAIN HOW TO DETERMINED THE E INTERSEPTION POINT BETWEEN THE CIRCLE X SQUARE PLUS Y SQUARE EQUAL TWENTY AND Y EQUAL X PLUS ONE
First, substituted y equal x plus one to x square plus y square equal twenty and we get new equation that is two x square plus two x minus nineteen equal zero. Then to know how many possible roots we can search determinant. Where, determinant equal b square minus four ac. So that, the equation have two root because the value of determinant more than zero. And know search the root. And the root is x. Then substitute x to the equation and we get y. x point y is interceptions point of two circle.
MAXIMUM AND MINIMUM VALUE (EXTREME VALUE)
Value of f(a) call maximum value at interval I, If f(a) more than f(x) to every x component of I. while Value of f(a) call minimum value at interval I, If f(a) less than f(x) to every x component of I.
The rule to determined maximum an minimum value:
· Definite first and second decrease, f’(x) and f’’(x)
· Definite stationary point from first decrease, f’(x) = 0, so that x = a
· Value f(a) as maximum value if f’’(a)<0, while value f(a) as minimum value if f’’(a)>0
Example:
Distance a motorcycle from a place calculate every at t with formula f(t) equal one to three over three minus seven square over two plus ten x. Determine maximum and minimum distance from a motorcycle.
Answer:
First, determine first and second decrease. We get of first decrease is x square minus seven x plus ten. And second decrease is two times x minus seven.
Then, determine stationer point with equally first decrease with zero. And we get two stationer points that is five and two. Then, substitute two stationer points to second decrease equation. And we get minus three for t equal two and three for t equal five. And from this situation we know that f (t) maximum on t equal two and minimum on t equal five. And substitute the stationer point to f (t) and we get maximum and minimum distance.
FIBONACCI SERIES
Unlimited Integer series, where, a number can be get from to count up two numbers before. And the formula like U0 equal U1 equal one. And U (n+1) equal U (n) plus U (n-1). And if we divide a number with number before, we can get value to approach one point six one eight. And this usually call Golden Ratio.
Sample of this series is 1, 1, 2, 3, 5, 8, 12, 13, 21, 34, 55, 89, 144........
Application of this series can be use to search how many rabbit in a room, where every a pair rabbit always produce a pair rabbit too.
PARALLEL EPIPEDUM
Parallel epipedum is prism where the base is parallelogram. So, like with ordinary prism and the different only in base.
Example we will search height of parallel epipedum with congruent parallelogram and we know area of parallel epipedum is thirty six and side of parallelogram is three. So to search the high of Parallel epipedum we must search area of each side with divide area with sum side that is thirty six with six and the result is six. And then we only searc high of side that is parallelogram with use formula base cross high. So the high of Parallel epipedum is divide six with three that is two.